256w^2-1=0

Solution for 256w^2-1=0 equation:

256w^2-1=0

a = 256; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·256·(-1)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*256}=\frac{-32}{512}
=-1/16
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*256}=\frac{32}{512}
=1/16
$